4^(2x)-4/(2^x-2)=126

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Solution for 4^(2x)-4/(2^x-2)=126 equation: 



4^(2x)-4/(2^x-2)=126

We move all terms to the left:

4^(2x)-4/(2^x-2)-(126)=0



Domain of the equation: (2^x-2)!=0

We move all terms containing x to the left, all other terms to the right

2^x!=2

x!=2/1

x!=2

x∈R



We multiply all the terms by the denominator


4^2x*(2^x-2)-126*(2^x-2)-4=0

We multiply parentheses

4^2x*(2^x-2)-252x+252-4=0

We add all the numbers together, and all the variables

-252x+4^2x*(2^x-2)+248=0

We move all terms containing x to the left, all other terms to the right

-252x+4^2x*(2^x-2)=-248

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